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What is f'(x) when f(x) = 10-10e**(-2x)?

Guest Apr 11, 2017
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 #1
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d/dx (e^(-2x) )      = -2e^(-2x)      from the Chain Rule.                 

So f'(x) =  -20 e^(-2x)

Guest Apr 11, 2017
 #3
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You've forgotten one of the minus signs Guest #1

Alan  Apr 11, 2017
 #2
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f'(x) = 0 - 10*(-2)e-2x  or  f'(x) = 20e-2x 

.

Alan  Apr 11, 2017

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