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# engineering

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a cylindrical tank is 8 meters long and 4 meters in diameter. How many liters of liquid will the tank hold?

Guest Sep 22, 2017

#1
+18777
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a cylindrical tank is 8 meters long and 4 meters in diameter.

How many liters of liquid will the tank hold?

Let d = Diameter of the cylindrical tank = 4 meters
Let r = Radius of the cylindrical tank $$\mathbf{= \frac{d}{2}=\frac{4}{2} = 2\, meters}$$
Let h = Height of the cylindrical tank = 8 meters
Let V = Volume of the cylindrical tank

$$\begin{array}{|rcll|} \hline V &=& \pi r^2 h \\ &=& \pi\cdot 2^2 \cdot 8\ m^3 \\ &=& 32\pi \ m^3 \\ &=& 100.530964915\ m^3 \\ &=& 100.530964915\ m^3 \times \frac{1000\ l}{1\ m^3} \\ &=& 100.530964915 \cdot 1000\ \text{liters} \\ &=& 100530.964915\ \text{liters} \\ \hline \end{array}$$

The Tank will hold 100531 liters

heureka  Sep 22, 2017
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#1
+18777
+1

a cylindrical tank is 8 meters long and 4 meters in diameter.

How many liters of liquid will the tank hold?

Let d = Diameter of the cylindrical tank = 4 meters
Let r = Radius of the cylindrical tank $$\mathbf{= \frac{d}{2}=\frac{4}{2} = 2\, meters}$$
Let h = Height of the cylindrical tank = 8 meters
Let V = Volume of the cylindrical tank

$$\begin{array}{|rcll|} \hline V &=& \pi r^2 h \\ &=& \pi\cdot 2^2 \cdot 8\ m^3 \\ &=& 32\pi \ m^3 \\ &=& 100.530964915\ m^3 \\ &=& 100.530964915\ m^3 \times \frac{1000\ l}{1\ m^3} \\ &=& 100.530964915 \cdot 1000\ \text{liters} \\ &=& 100530.964915\ \text{liters} \\ \hline \end{array}$$

The Tank will hold 100531 liters

heureka  Sep 22, 2017

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