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# Equation (show work)

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Write the equation for a line that has a slope of -2 and passes though the point (4,7)

Guest Aug 1, 2017

#1
+1493
+1

In order to do this problem, you must understand not slope-intercept form but point-slope form.

Point-slope form is the following equation:

\(y-k=m(x-h)\)

m = slope of the line

(h,k) is a point (any point will do) on the line.

We already have all of this information given to us already, so this problem is relatively easy. m = -2 and (h,k) is (4,7). Let's plug this in:

 \(y-k=m(x-h)\) Plug in m as -2, h as 4, and k as 7. \(y-7=-2(x-4)\) You could say that you are done because you have written an equation for the conditions, but let's transform this into slope-intercept form by distributing the -2. \(y-7=-2x+8\) Add 7 to both sides. \(y=-2x+15\)
TheXSquaredFactor  Aug 1, 2017
Sort:

#1
+1493
+1

In order to do this problem, you must understand not slope-intercept form but point-slope form.

Point-slope form is the following equation:

\(y-k=m(x-h)\)

m = slope of the line

(h,k) is a point (any point will do) on the line.

We already have all of this information given to us already, so this problem is relatively easy. m = -2 and (h,k) is (4,7). Let's plug this in:

 \(y-k=m(x-h)\) Plug in m as -2, h as 4, and k as 7. \(y-7=-2(x-4)\) You could say that you are done because you have written an equation for the conditions, but let's transform this into slope-intercept form by distributing the -2. \(y-7=-2x+8\) Add 7 to both sides. \(y=-2x+15\)
TheXSquaredFactor  Aug 1, 2017

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