Write the equation for a line that has a slope of -2 and passes though the point (4,7)
In order to do this problem, you must understand not slope-intercept form but point-slope form.
Point-slope form is the following equation:
\(y-k=m(x-h)\)
m = slope of the line
(h,k) is a point (any point will do) on the line.
We already have all of this information given to us already, so this problem is relatively easy. m = -2 and (h,k) is (4,7). Let's plug this in:
\(y-k=m(x-h)\) | Plug in m as -2, h as 4, and k as 7. |
\(y-7=-2(x-4)\) | You could say that you are done because you have written an equation for the conditions, but let's transform this into slope-intercept form by distributing the -2. |
\(y-7=-2x+8\) | Add 7 to both sides. |
\(y=-2x+15\) | |
In order to do this problem, you must understand not slope-intercept form but point-slope form.
Point-slope form is the following equation:
\(y-k=m(x-h)\)
m = slope of the line
(h,k) is a point (any point will do) on the line.
We already have all of this information given to us already, so this problem is relatively easy. m = -2 and (h,k) is (4,7). Let's plug this in:
\(y-k=m(x-h)\) | Plug in m as -2, h as 4, and k as 7. |
\(y-7=-2(x-4)\) | You could say that you are done because you have written an equation for the conditions, but let's transform this into slope-intercept form by distributing the -2. |
\(y-7=-2x+8\) | Add 7 to both sides. |
\(y=-2x+15\) | |