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why is it that when u do 0! it is 1

Guest May 1, 2017
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9! = 9 * 8 * 7 * ... * 2 * 1 = 9 * (8 * 7 * ... * 2 * 1) = 9 * 8!

8! = 8 * 7 * ... * 2 * 1 = 8 * (7 * ... * 2 * 1) = 7 * 8!

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2! = 2 * 1 = 2 * (1) = 2 * 1!

 

Hence, we can see that n! = n * (n-1)!

So, using n = 1, we can see that 1! = 1 * 0!, which simplifies to 1 = 0!

ThisGuy  May 1, 2017

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