Hello. How would I factor the following?
7(x-1)-x(x+1)
a2-36
b2+5b+6
Thank you!
+33614
a2-36
This is a standard difference of two squares so: a2 - 36 → a2 - 62 → (a+6)(a-6)
b2+5b+6 → (b + 2)(b + 3)
7(x-1)-x(x+1) doesn't factor nicely at all as far as I can see!
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+118608 For questions like
\(b^2+5b+6\)
you need to look for 2 numbers that multiply to be +6
Since it is + they both must be + or both -
BUT
they have to add to be +5 so they both must be +
ok
we have
1*6=6 but 1+6 is not 5
2*3=6 and 2+3=5 BINGO!
so we have
\(b^2+5b+6=(b+2)(b+3)\)
Just like Alan said :)))
