fibonnaci numbers to the 43rd digit..what is the exact number for the golden rule to break it down perfectly
1 6 6 7 3 5 1 2 8 2 7 1 6 2 2 6 6 3 4 8 6 2 9 3 8 3 7 2 0 5 2 5 0 8 3 5 5 7 4 2 8 2 7
+33615 Are you asking about the Binet formula? This gives the n'th standard Fibonacci number as
$$\frac{(1+\sqrt5)^n-(1-\sqrt5)^n}{2^n\sqrt5}$$
However, this doesn't reproduce the number you've written (yours lies between the 203rd and 204th standard Fibonacci numbers).
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