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I missed class, and im having trouble with this.

Guest May 24, 2017
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Let   f(x)  = 2 u * v    where

u  = sin (4x)

v= sin-1 (x)   =  arcsin (x)

 

Using the product and chain rules :

 

f ' (x)  =   2 [  u ' * v +  u * v ' ]

 

So

 

f  ' (x)  =  2  [   4cos (4x)* arcsin (x)  +  sin (4x) *   1 / √ (1 - x^2 ) ] =

 

 

8cos(4x)arcsin (x)  +  2 sin (4x) / √ (1 - x^2 )

 

 

cool cool cool

CPhill  May 24, 2017
edited by CPhill  May 24, 2017

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