+0

# Find the area of trapezoid DUCK shown below.

+2
216
2
+206

Find the area of trapezoid DUCK shown below.

waffles  Apr 24, 2017

#1
+4808
+3

area of a trapezoid = (1/2)(first base + second base)(height)

52 + height2 = 132 → height = $$\sqrt{144}=12$$

first base = $$5+15+\sqrt{20^2-12^2}=5+15+\sqrt{256}=36$$

second base = 15

area = (1/2)(36 + 15)(12) = (6)(51) = 306 sq. un.

hectictar  Apr 24, 2017
Sort:

#1
+4808
+3

area of a trapezoid = (1/2)(first base + second base)(height)

52 + height2 = 132 → height = $$\sqrt{144}=12$$

first base = $$5+15+\sqrt{20^2-12^2}=5+15+\sqrt{256}=36$$

second base = 15

area = (1/2)(36 + 15)(12) = (6)(51) = 306 sq. un.

hectictar  Apr 24, 2017
#2
+54
+2

area of trapezoid = height * (a + b) / 2

Height = sqrt(132 - 52) = sqrt(144)     »»»     sqrt(144) = 12

a = 15

b = DK = 5 + 15 + sqrt(202 - height2)     »»»    20 + sqrt(202 - 122) = 20 + sqrt(256) = 36

area = 12 * (15 + 36) / 2     »»»     6 * 51 = 306 units2

Doboman  Apr 24, 2017

### 8 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details