+0  
 
+1
34
1
avatar+148 

Find the equation of the line that passes through these two points:

(-6, -13) and (6, -1)

Tiffybean  Nov 3, 2017

Best Answer 

 #1
avatar+634 
+2

To find the slope of a line, the equation is \(\frac{y_2-y_1}{x_2-x_1}\).

Plug in the point values.

\(\frac{-1+13}{6+6}\)

Simplify.

\(\frac{-1+13}{6+6}=\frac{12}{12}=1\)

So the slope is 1. Now use point-slope form, which is \(y-y_1=m(x-x_1)\).

Now, it doesn't matter which point you plug in. I'll use (-6,-13).

\(y+13=1(x+6)\)

Distribute the 1.

\(y+13=x+6\)

Subtract the 13 from both sides.

\(y=x-7\)

AdamTaurus  Nov 3, 2017
Sort: 

1+0 Answers

 #1
avatar+634 
+2
Best Answer

To find the slope of a line, the equation is \(\frac{y_2-y_1}{x_2-x_1}\).

Plug in the point values.

\(\frac{-1+13}{6+6}\)

Simplify.

\(\frac{-1+13}{6+6}=\frac{12}{12}=1\)

So the slope is 1. Now use point-slope form, which is \(y-y_1=m(x-x_1)\).

Now, it doesn't matter which point you plug in. I'll use (-6,-13).

\(y+13=1(x+6)\)

Distribute the 1.

\(y+13=x+6\)

Subtract the 13 from both sides.

\(y=x-7\)

AdamTaurus  Nov 3, 2017

6 Online Users

avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details