+128458 3x+5y-8=0 that passes through the point (-8,1)
We have the form Ax + BY + C = 0 and the slope of this line is just -A/B = -3/5
And a perpendicular line will have negative reciprocal slope = 5/3
And using the point-slope form, we have
y = (5/3)(x + 8) - 1
y = (5/3)x + 40/3 - 1
y = (5/3)x + 37/3
In standard form, we have
5x - 3y + 37 = 0
Here's the graph of both lines
+128458 3x+5y-8=0 that passes through the point (-8,1)
We have the form Ax + BY + C = 0 and the slope of this line is just -A/B = -3/5
And a perpendicular line will have negative reciprocal slope = 5/3
And using the point-slope form, we have
y = (5/3)(x + 8) - 1
y = (5/3)x + 40/3 - 1
y = (5/3)x + 37/3
In standard form, we have
5x - 3y + 37 = 0
Here's the graph of both lines
