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(3+2i)/(1+2i+i^(2))

 Feb 22, 2017
 #1
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(3+2i)/(1+2i+i^(2)) =

 

(3 + 2i)/ (1 + 2i - 1) =

 

(3 + 2i) / (2i)      multiply top/bottom by2i

 

(6i + 4i^2) / (4i^2)  =

 

(6i  - 4) / (-4)  =

 

(4 - 6i) /(4)  =

 

(2 - 3i) / 2 =

 

1 - (3/2)i

 

 

cool cool cool

 Feb 22, 2017

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