Since sin x can't be bigger than 1, assuming this is the question
cos (2x + 2) = sin x
*edit* That was a bad thing to assume!
This is probably not the answer you want.. see CPhill's answer vvvv
But if you did happen to mean that:
This is to make it easier to see that
x + (2x + 2) = 90
x + 2x + 2 = 90
3x = 88
x = 88/3
cos 2x + 2 = sin x
1 - 2sin^2x + 2 = sinx
2sin^2x + sinx - 3 = 0
(2sin x + 3) ( sin x - 1) = 0
The first factor has no solution
For the second, we have
sin x - 1 = 0
sin x = 1 and this happens at pi/2 + 2pi*n where n is an integer
See the graph here showing the intersection points :
https://www.desmos.com/calculator/31maw6isd8