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# Find the total cost of producing 6 widgets.

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Find the total cost of producing 6 widgets.

Widget Wonders produces widgets. They have found that the cost, c(x), of making x widgets is a quadratic function in terms of x. The company also discovered that it costs $23 to produce 2 widgets,$103 to produce 4 widgets, and \$631 to produce 10 widgets.

Guest Jun 27, 2014

#1
+10

If c(x) is a quadratic function, then $${c}{\left({\mathtt{x}}\right)} = {\mathtt{A}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{B}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{C}}$$, where A, B, and C are constants. Our job here is to find the constants.

$$c(2) = 23 = A*2^2 + B*2 + C$$

$$c(4) = 103 = A*4^2 + B*4 + C$$

$$c(10) = 631 = A*10^2 + B*10 + C$$

So we have:

$$23 = 4A + 2B + C$$

$$103 = 16A + 4B + C$$

$$631 = 100A + 10B + C$$

If we solve that, we get A = 6, B = 4, C = -9.
Thus, since $${c}{\left({\mathtt{x}}\right)} = {\mathtt{A}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{B}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{C}}$$:

$$c(x) = 6x^2+4x-9$$

Now we just use the function for x=6.
$${c}{\left({\mathtt{6}}\right)} = {\mathtt{6}}{\mathtt{\,\times\,}}{{\mathtt{6}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{6}}{\mathtt{\,-\,}}{\mathtt{9}}$$
$$c(6) = 231$$ dollars.

Guest Jun 27, 2014
Sort:

#1
+10

If c(x) is a quadratic function, then $${c}{\left({\mathtt{x}}\right)} = {\mathtt{A}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{B}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{C}}$$, where A, B, and C are constants. Our job here is to find the constants.

$$c(2) = 23 = A*2^2 + B*2 + C$$

$$c(4) = 103 = A*4^2 + B*4 + C$$

$$c(10) = 631 = A*10^2 + B*10 + C$$

So we have:

$$23 = 4A + 2B + C$$

$$103 = 16A + 4B + C$$

$$631 = 100A + 10B + C$$

If we solve that, we get A = 6, B = 4, C = -9.
Thus, since $${c}{\left({\mathtt{x}}\right)} = {\mathtt{A}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{B}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{C}}$$:

$$c(x) = 6x^2+4x-9$$

Now we just use the function for x=6.
$${c}{\left({\mathtt{6}}\right)} = {\mathtt{6}}{\mathtt{\,\times\,}}{{\mathtt{6}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{6}}{\mathtt{\,-\,}}{\mathtt{9}}$$
$$c(6) = 231$$ dollars.

Guest Jun 27, 2014
#2
+91454
0

Very nicele done anonymous!  Thumbs up from me.

Why don't you join up.  It is really easy now-a-days.

We'd love to get to know you.

Melody  Jun 28, 2014
#3
0

is that right

Guest Jun 1, 2016

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