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1. find the value of x^2 + 2xy + y^2 if x + y =12

2. (x + 3)^2 - (x + 1)^2

3. simplify (1/b - 1/a) x (b/a - a/b)

4. x^2 + x + 1/4

 

thankyou

 May 17, 2015

Best Answer 

 #1
avatar+128085 
+5

x^2 + 2xy + y^2 =  (x + y)(x + y) =  (12)(12) =  144

 

(x + 3)^2 - (x +  1)^2    =    [ (x + 3) + (x + 1) ] [ (x + 3) - (x + 1) ]  =  [2x + 4] [ 2] = 2[x + 2] [2]  = 4[x + 2]  = 4x + 8

 

(1/b - 1/a) x (b/a - a/b)  =  [ 1/a - b/a^2 - a/b^2 + 1/b]     [there are other possible forms]

 

x^2 + x + 1/4  = (x + 1/2)(x + 1/2)  = (x + 1/2)^2

 

 

 May 17, 2015
 #1
avatar+128085 
+5
Best Answer

x^2 + 2xy + y^2 =  (x + y)(x + y) =  (12)(12) =  144

 

(x + 3)^2 - (x +  1)^2    =    [ (x + 3) + (x + 1) ] [ (x + 3) - (x + 1) ]  =  [2x + 4] [ 2] = 2[x + 2] [2]  = 4[x + 2]  = 4x + 8

 

(1/b - 1/a) x (b/a - a/b)  =  [ 1/a - b/a^2 - a/b^2 + 1/b]     [there are other possible forms]

 

x^2 + x + 1/4  = (x + 1/2)(x + 1/2)  = (x + 1/2)^2

 

 

CPhill May 17, 2015

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