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Thanks CPhill, follow up question:

 

A ball travels on a parabolic path in which the height (in feet) is given by the expression -16t^2+32t+15, where t is the time after launch. What is the maximum height of the ball?

WhichWitchIsWhich  Oct 23, 2017
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 #1
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+1

In the form ax^2 + bx + c.....the x coordinate of the max height occurs at

 

-b / [ 2a]  =  -32 / [ 2 (-16) ]  =  1

 

So.....the max height is   -16(1)^2 + 32(1) + 15  =  31 ft 

 

Here's the graph :  https://www.desmos.com/calculator/tp0ornpndr

 

 

cool cool cool

CPhill  Oct 23, 2017

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