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For any triangle ABC, prove that a+b = cos A-B/2

                                                      2       sin c/2

Guest Feb 23, 2017

Best Answer 

 #2
avatar+18766 
+20

Do you mean

Mollweide's Formula ?
\((a+b)\sin\frac{C}{2}=c \cdot cos\left(\frac{A-B}{2}\right) \)

 

laugh

heureka  Feb 23, 2017
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2+0 Answers

 #1
avatar+91223 
+5

For any triangle ABC, prove that a+b = cos A-B/2

                                                      2       sin c/2

 

 

Do you mean

 

For any triangle ABC,  prove that

 

\(\frac{a+b}{2}=\frac{cos(A-\frac{B}{2})}{sin(\frac{C}{2})}\)

Melody  Feb 23, 2017
 #2
avatar+18766 
+20
Best Answer

Do you mean

Mollweide's Formula ?
\((a+b)\sin\frac{C}{2}=c \cdot cos\left(\frac{A-B}{2}\right) \)

 

laugh

heureka  Feb 23, 2017

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