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\frac{\sqrt{2}+\sqrt{7}}{\sqrt{8}+\sqrt{7}}

 Apr 7, 2015

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 #1
avatar+118587 
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$$\frac{\sqrt{2}+\sqrt{7}}{\sqrt{8}+\sqrt{7}}\\\\
=\frac{(\sqrt{2}+\sqrt{7})(\sqrt{8}-\sqrt{7})}{(\sqrt{8}+\sqrt{7})(\sqrt{8}-\sqrt{7})}\\\\
=\frac{\sqrt{16}-\sqrt{14}+\sqrt{56}-7}{(8-7)}\\\\
=\frac{4-\sqrt{14}+\sqrt{4*14}-7}{(1)}\\\\
=4-\sqrt{14}+2\sqrt{14}-7\\\\
=-3+\sqrt{14}\\\\
=\sqrt{14}-3\\\\$$

.
 Apr 8, 2015
 #1
avatar+118587 
+5
Best Answer

$$\frac{\sqrt{2}+\sqrt{7}}{\sqrt{8}+\sqrt{7}}\\\\
=\frac{(\sqrt{2}+\sqrt{7})(\sqrt{8}-\sqrt{7})}{(\sqrt{8}+\sqrt{7})(\sqrt{8}-\sqrt{7})}\\\\
=\frac{\sqrt{16}-\sqrt{14}+\sqrt{56}-7}{(8-7)}\\\\
=\frac{4-\sqrt{14}+\sqrt{4*14}-7}{(1)}\\\\
=4-\sqrt{14}+2\sqrt{14}-7\\\\
=-3+\sqrt{14}\\\\
=\sqrt{14}-3\\\\$$

Melody Apr 8, 2015

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