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# Geometry Help?

-1
28
1
+68

https://prnt.sc/hxpamx

https://prnt.sc/hxpaw2

https://prnt.sc/hxpb51

https://prnt.sc/hxpbd3

Severoth  Jan 8, 2018
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#1
+80874
+2

First one  :

YP / PX  = YQ / QZ

16 / 5  =   8 / 2.5

Second  one :

For QS  to be parallel to MN....we must have that

QM * NR   =  SN * MR

2 * 5   =  3 * 4        Not parallel

2 * 15  =   6 * 5     Parallel

2 * 12  =  3 * 8      Parallel

Third one  :

The angle bisector sets up the following relationship

YZ   / MY   =  XZ  / MX

7 / 3.5   =  11  /   MX

2  =   11 / MX      rearrange as

MX  = XM  =   11/2   =    5.5

Last one :

Let  WZ    =  x

So.....WY  =  8  - x

And we have the following relationship

WY / XY  = WZ / XZ

[ 8 - x ]  /  6.5   =   x  / 6            cross-multiply

6 [ 8 - x ]   =  6.5x

48  -  6x   =  6.5 x        add 6x to both sides

48  =  12.5 x              divide both sides by 2.5

3.84    =  x   =     WZ

CPhill  Jan 8, 2018

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