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# Geometry

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In quadrilateral \$ABCD\$, we have \$AB = BC = CD = DA\$, \$AC = 14\$, and \$BD = 48\$. Find the perimeter of \$ABCD\$.

eileenthecoolbean  Aug 9, 2017

#1
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Thus if s=length of each side of the rhombus, then
\(s²=(AC/2)²+(BD/2)²\)
using Pythagoras theorem.
Calculate (Multiply S by 4 to get final answer because all four sides are equal)
\(s=√(7²+24²)  =25 \)

RektTheNoob  Aug 9, 2017
edited by RektTheNoob  Aug 9, 2017
Sort:

#1
+74
+3

Thus if s=length of each side of the rhombus, then
\(s²=(AC/2)²+(BD/2)²\)
using Pythagoras theorem.
Calculate (Multiply S by 4 to get final answer because all four sides are equal)
\(s=√(7²+24²)  =25 \)

RektTheNoob  Aug 9, 2017
edited by RektTheNoob  Aug 9, 2017

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