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how do I get angle of a triangle not right angled when I know three sides

Guest Mar 10, 2017
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how do I get angle of a triangle not right angled when I know three sides

 

\(Cosine \ set\)

 

\(a^2=b^2+c^2-2bc\ cos\alpha\)

 

\(\alpha=arccos\frac{b^2+c^2-a^2}{2bc}\)

 

\(\beta=arccos\frac{a^2+c^2-b^2}{2ac}\)

 

\(\gamma=arccos\frac{a^2+b^2-c^2}{2ab}\)

 

laugh  !

asinus  Mar 10, 2017

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