Given the equation y=4x-3 , If x increases by 1 unit, what is the corresponding change in y
Thanks Heureka,
I just want to look at this a little differently.
y=4x-3
$$gradient= \frac{rise}{run}= \frac{change \;in\; y}{change\;in\;x}=\frac{4}{1}$$
so if x changes by 1 unit y changes by 4. That is just another way to look at the gradient :)
The gradient IS the change in y if x increases by 1 unit.
Given the equation y=4x-3 , If x increases by 1 unit, what is the corresponding change in y
$$y_1=4x-3\\
y_2=4(x+1)-3\\
y_2=4x+4-3\\
y_2=\underbrace{4x-3}_{=y_1}+4 \\
y_2=y_1+4\\
y_2-y_1=\Delta y = 4$$
the corresponding change in y is 4
Thanks Heureka,
I just want to look at this a little differently.
y=4x-3
$$gradient= \frac{rise}{run}= \frac{change \;in\; y}{change\;in\;x}=\frac{4}{1}$$
so if x changes by 1 unit y changes by 4. That is just another way to look at the gradient :)
The gradient IS the change in y if x increases by 1 unit.