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greatest common divisors of 23^31 , 23^17

Guest Jan 19, 2015

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 #3
avatar+18827 
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greatest common divisors (GCD) of 23^31 , 23^17


$$\small{\begin{array}{l|rclclclcl}\text{Number 1:} & 23^{31} &=& 23^{31} &&&&&& \\
\text{Number 2:} & 23^{17} &=& 23^{\textcolor[rgb]{1,0,0}{17}} && && && \\
\hline \text{The lowest Exponent}\\ \text{ of each prime number} &\text{GCD}&=& 23^{\textcolor[rgb]{1,0,0}{17}}&&&&&&
\end{array}}}$$

heureka  Jan 19, 2015
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 #1
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it is 1 because the numbers are prime

Guest Jan 19, 2015
 #2
avatar+26397 
+5

The gcd is 23^17 because it goes into itself once and into 23^31 23^14 times.

.

Alan  Jan 19, 2015
 #3
avatar+18827 
+5
Best Answer

greatest common divisors (GCD) of 23^31 , 23^17


$$\small{\begin{array}{l|rclclclcl}\text{Number 1:} & 23^{31} &=& 23^{31} &&&&&& \\
\text{Number 2:} & 23^{17} &=& 23^{\textcolor[rgb]{1,0,0}{17}} && && && \\
\hline \text{The lowest Exponent}\\ \text{ of each prime number} &\text{GCD}&=& 23^{\textcolor[rgb]{1,0,0}{17}}&&&&&&
\end{array}}}$$

heureka  Jan 19, 2015

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