A square is inscribed in a circle of radius 5 centimeters. What is the value of \(x^2+y^2\)
The opposite vertices of a square are the endpoints of a diameter of that square.
Therefore, the angle between the x- and y-sides of the square is a right angle and x and y are the sides of a right triangle.
Since the radius of the circle is 5, its diameter is 10:
x2 + y2 = 102.
The opposite vertices of a square are the endpoints of a diameter of that square.
Therefore, the angle between the x- and y-sides of the square is a right angle and x and y are the sides of a right triangle.
Since the radius of the circle is 5, its diameter is 10:
x2 + y2 = 102.