+72 Determine the value of (P+Q) given that: Plog4005 + Qlog4002 = 3
Hi, I've been having trouble lately with this question. I've tried completing it, but so far I have only got up to this:
Plog4005 + Qlog4002 = 3
log400(5p x 2q) = 3
I'm stuck on what to do next, your help will much be appreciated! Thanks!
+118608 Hi MapleTheopry,
This is an unusual question. :)
\(Plog_{400}5+Qlog_{400}2=3\\ log_{400}(5^P)+log_{400}(2^Q)=3\\ log_{400}(5^P*2^Q)=3\\~\\ 400^3=5^P*2^Q\\ (2^4*5^2)^3=5^P*2^Q\\ 2^{12}*5^6=2^Q*5^P\\ so\\ P+Q=6+12=18 \)
+118608 For some reason LaTex is not displaying properly.
If you cannot make sense of my answer let me know and I will try to write it without LaTex. :/
+72 No, its fine. I got up to 4003= 5p x 2q , but never thought of converting 400 to (24 x 52). Wow! Thanks very much Melody!
