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If a mecahnic can install 12 motorss in 18 3/4 hours, how many motors should he be able to install in 28 1/8 hours?

Guest Nov 5, 2017
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 #1
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We can solve with a proportion

 

12   / [ 18 + 3/4 ]  =   M  / [ 28 + 1/8 ]      cross-multiply

 

12 [ 28 + 1/8 ]   = [ 18 + 3/4 ] M

 

12 [ 225 / 8 ]  = [75 / 4 ] M      mutiply through by 8

 

12 * 225  =  150 M

 

2700  =  150 M     divide both sides by 150

 

18  = M   ⇒  18 motors in  28 + 1/8 hrs

 

 

cool cool cool

CPhill  Nov 5, 2017

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