When the expression\(\) \(-2x^2-20x-53\) is written in the form \(a(x+d)^2+e\), where \(a\), \(d\), and \(e\) are constants, then what is the sum \(a+d+e\)?
-2x^2 - 20x - 53 complete the square
-2 ( x^2 + 10x + 25 + 53/2 - 25)
-2 [ (x + 5)^2 + 53/2 - 50/2 )
-2 [ (x + 5)^2 + 3/2 ]
-2( x + 5)^2 - 3
a = -2 d = 5 e = -3
And their sum = 0
