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How do I solve this?

A right angled triangle has sides 4cm and 8cm respectively less than in hypotenuse. Find the length of each side of the triangle.

 May 24, 2014

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 #3
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Thankss for answering! it really helped! 

 May 25, 2014
 #1
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pythagorean theory. not an 100% sure it will work but try it out. if not best way= regoogle it.

 May 24, 2014
 #2
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Let h be the length of the hypoteneuse. Then by the Pythagorean Theorem, we have

(h-4)^2 +  (h-8)^2 = h^2       Expanding the terms, we have

h^2 - 8h + 16 + h^2 - 16h + 64 = h^2        And simplifying

2h^2  - 24h + 80 = h^2         Subtract h^2 from both sides

h^2 - 24h + 80 = 0               And factoring, we have

(h -20) (h-4) = 0             Reject h =4, since it would make one side 0 and the other -4

So the hypoteneuse is 20 and, one side = (20-4) = 16, and the other side = (20 - 8) = 12

 May 24, 2014
 #3
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Thankss for answering! it really helped! 

Guest May 25, 2014

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