How do I solve this?
A right angled triangle has sides 4cm and 8cm respectively less than in hypotenuse. Find the length of each side of the triangle.
pythagorean theory. not an 100% sure it will work but try it out. if not best way= regoogle it.
Let h be the length of the hypoteneuse. Then by the Pythagorean Theorem, we have
(h-4)^2 + (h-8)^2 = h^2 Expanding the terms, we have
h^2 - 8h + 16 + h^2 - 16h + 64 = h^2 And simplifying
2h^2 - 24h + 80 = h^2 Subtract h^2 from both sides
h^2 - 24h + 80 = 0 And factoring, we have
(h -20) (h-4) = 0 Reject h =4, since it would make one side 0 and the other -4
So the hypoteneuse is 20 and, one side = (20-4) = 16, and the other side = (20 - 8) = 12