+0

# Help me with this please sqrt(20)+sqrt(500)+sqrt(80)=nsqrt(5) find N

0
71
2

Help me with this please sqrt(20)+sqrt(500)+sqrt(80)=nsqrt(5) find N

Guest Oct 9, 2017
Sort:

#1
0

Solve for n:

sqrt(20)+sqrt(500)+sqrt(80)=nsqrt(5)   factor the LHS as follows:

sqrt(4x5) + Sqrt(100x5) + sqrt(16x5) =nsqrt(5)

2sqrt(5) + 10sqrt(5) + 4sqrt(5) = nsqrt(5)  factor sqrt(5) on the LHS

sqrt(5)(4+10+2) =nsqrt(5)                             divide both sides by sqrt(5)

n =2+10+4

n=16

Guest Oct 9, 2017
edited by Guest  Oct 9, 2017
#2
+69
0

n=16

sqrt(20)+sqrt(500)+sqrt(80)=nsqrt(5)

Switch around terms

n*sqrt{5}=sqrt{20}+sqrt{500}+sqrt{80}

Find radicals of sqrt{20}, sqrt{500} and sqrt{80}

sqrt{20}= 2 sqrt{5}

sqrt{500} = 10 sqrt{5}

sqrt{80} = 4 sqrt{5}

n*sqrt{5}=16sqrt{5}

Divide by sqrt{5}

n=16

NediaMaster  Oct 9, 2017

### 28 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details