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Find K if 2^K = 8(sevenroot32)

 Jan 18, 2017
 #1
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+5

2^K = 8 * 32^(1/7)

 

2^K  = [2]^3 * [2^5]^(1/7)

 

2^K  = [2]^3* *  [2]]^(5/7)

 

2^K =  2^[ 3 + 5/7]     →    K =  3 + 5/7 =   26 / 7

 

 

 

cool cool cool

 Jan 19, 2017

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