#1**0 **

If you want the hypotenuse.... √ [ (leg 1)^2 + (leg 2)^2 ]

If you want a leg ..... √ [ ( hypotenuse)^2 - (leg)^2 ]

CPhill
Feb 28, 2017

#2**0 **

Ok, I am going ot give you a simple answer, the pythagorean theorem. Which is a^{2 }+ b^{2 }= c^{2}

So if you have a normal right triangle, like this one, you'd use the theorem. First you'd do 5^{2 }+ b^{2} = 12^{2}.

The reason we don't know what b squared is because that is what we're finding. 5^{2 }= 25 and 12^{2} = 144 so fill in the equation. 25 + b^{2 }= 144. Now subtract 25 from both sides. Now you get b^{2 }= 119. Now you have to remove the squared in b^{2}. Since you have to remove the power, you have to find the square root of both sides. So in b^{2 }= 119, do the square root to both sides. So now you get your answer as b = 10.908. If you just want the longest side(hypotenuse), you do a^{2 }+ b^{2 } = c^{2}. I am going to pick random numbers, let's say a is 5 and b is 6. So, 5^{2} + 6^{2} = c^{2}. 5 squared is 25 and 6 squared is 36. So 25 + 36 = c^{2}. 61 = c^{2}. So now you have to find the square root of both sides. The answer is 7.81.

Guest Feb 28, 2017