+0  
 
+1
40
4
avatar+245 

English has 6 letters that can be vowels. This includes Y, which can be either a consonant or a vowel; for this problem, we'll consider Y a vowel.

The other 20 English letters are always consonants.

How many two-letter "words" can we make from these letters if we are required to use at least one vowel? (We aren't limited to words that have an actual meaning in English. Thus, for this problem, we'll include nonsense "words" like QO, XY, and UZ.)

 
SmartMathMan  Jan 9, 2018
edited by Guest  Jan 9, 2018
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4+0 Answers

 #1
avatar+116 
0

i am not sure but you can ask google

 
Nerd123  Jan 9, 2018
 #2
avatar+245 
0

really

...... -_-

 
SmartMathMan  Jan 9, 2018
 #3
avatar+245 
0

I AM NOT THE SAME GUEST THAT WAS POSTING THOSE OTHER THINGS I ONLY POSTED A FEW QUESTIONS 

 
SmartMathMan  Jan 9, 2018
 #4
avatar+80793 
+1

Number of words that can be made with one vowel and one consonant  =

 

[ Choose one vowel and one consonant.....and the reverse order of this  ]   =

 

6 * 20  *  2   =    240

 

Number of words that can be made with the same vowel repeated = 6

 

Number of words that can be made with two dissimilar vowels  =

 

Permute any 2 of the vowels out of 6 =

 

 P(6,2)  = 30

 

So.....the total number of possible "words"  is

 

240 + 6 +  30   =

 

276 

 

 

cool cool cool

 
CPhill  Jan 10, 2018

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