The Oddville Academy offers three languages: Oriya, Dakhini, and Dutch (how odd!). Each student takes an odd number of languages – that is, every student takes either one language or three languages.
Let x be the number of students taking Oriya, y be the number of students taking Dakhini, z be the number of students taking Dutch, and t be the number of students taking all three languages. Find an expression in terms of x, y, z, and t for the total number of students at the Oddville Academy.
+118608 You are very observant about those first letters ZZZ... but your logic is just a little off :))
There are t students taking all three and the rest take only 1 language so
The number taking only Oriya is x-t
The number taking only Dakhini is y-t
The number taking only Dutch is z-t
So the number of students altogether is
x-t + y-t + z-t + t = x+y+z-2t
+476 x+y+z+t=number of students at Oddville Academy
(Also I noticed that the languages' first letters spell "odd")
+118608 You are very observant about those first letters ZZZ... but your logic is just a little off :))
There are t students taking all three and the rest take only 1 language so
The number taking only Oriya is x-t
The number taking only Dakhini is y-t
The number taking only Dutch is z-t
So the number of students altogether is
x-t + y-t + z-t + t = x+y+z-2t
