+0  
 
0
70
4
avatar+230 

\(P\)  is the midpoint of  \(\overline{BD}\)\(AP = BP = 4\)\(\overline{AP} \perp \overline{BD}\)\(\overline{BD} \perp \overline{DC}\) , \(\overline{AB} \perp \overline{BC}\)  . In simple radical form,

what is the perimeter of pentagon  \(ABCDP?\)

ant101  Jul 21, 2017

Best Answer 

 #1
avatar+25984 
+1

ABPA:  \(p_1=4+4+4\sqrt2 \)

 

BCDB: \(p_2=8+8+8\sqrt2 \)

 

BP:   \(p_3=4\)

 

ABCDPA: \(p=p_1+p_2-p_3\rightarrow20+12\sqrt2\)

Alan  Jul 21, 2017
edited by Alan  Jul 21, 2017
edited by Alan  Jul 21, 2017
Sort: 

3+0 Answers

 #1
avatar+25984 
+1
Best Answer

ABPA:  \(p_1=4+4+4\sqrt2 \)

 

BCDB: \(p_2=8+8+8\sqrt2 \)

 

BP:   \(p_3=4\)

 

ABCDPA: \(p=p_1+p_2-p_3\rightarrow20+12\sqrt2\)

Alan  Jul 21, 2017
edited by Alan  Jul 21, 2017
edited by Alan  Jul 21, 2017
 #3
avatar+230 
0

its wrong

ant101  Jul 28, 2017
 #4
avatar
0

That is right!!!!!!! . I gave the right answer, which is 16 + 12sqrt(2), but they wouldn't accept it!!!!!.

Guest Jul 28, 2017

6 Online Users

avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details