Help.
Find the radius vector: missing side.
1. x=3, y=4
2. y=-5, r=13
3.x=3, r=5
I am not at all sure what you mean Kathh22 :(
1. x=3, y=4
I don't think this is what you want but.....
ok well you just want the distance of the point from the origin.
I already did the first one.
Draw a sketch on a number plane to get the idea.
2. y=-5, r=13
This is saying that the hypotenuse is 13 and the y direction is -5 units
so
\(x^2=13^2-(-5)^2\qquad \mbox{ it is minus cause you are finding the short side of a right angled triangle}\\ x^2=169-25\\ x^2=144\\ x=+12\quad or \quad x=-12 \)
3. x=3, r=5
\(x^2=25-9\\ x^2=16\\ x=\pm4\)
Think about it and if you still do not understand then let me know :))