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Help.

Find the radius vector: missing side.

1. x=3, y=4
2. y=-5, r=13
3.x=3, r=5

 Jun 26, 2016

Best Answer 

 #4
avatar+185 
+10

I mam, i already answered the 3. i think it goes to the formula of phytagoreas. thanks much. one last question mam? :)

 Jun 26, 2016
 #1
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I am not at all sure what you mean Kathh22 :(

 

1. x=3, y=4

 

I don't think this is what you want but.....

 

 Jun 26, 2016
 #2
avatar+185 
+10

Hi mam, this is the sample that our prof gave

kathh22  Jun 26, 2016
 #3
avatar+118608 
+10

ok well you just want the distance of the point from the origin.

I already did the first one.

Draw a sketch on a number plane to get the idea.

 

2. y=-5, r=13

 

This is saying that the hypotenuse is 13 and the y direction is -5 units

so

\(x^2=13^2-(-5)^2\qquad \mbox{ it is minus cause you are finding the short side of a right angled triangle}\\ x^2=169-25\\ x^2=144\\ x=+12\quad or \quad x=-12 \)

 

 

 


3.  x=3, r=5

\(x^2=25-9\\ x^2=16\\ x=\pm4\)

 

Think about it and if you still do not understand then let me know :))

 Jun 26, 2016
 #4
avatar+185 
+10
Best Answer

I mam, i already answered the 3. i think it goes to the formula of phytagoreas. thanks much. one last question mam? :)

kathh22  Jun 26, 2016
 #5
avatar+118608 
+10

Yes it is just the Pythagorean theorem :))

 Jun 26, 2016

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