The measure of the angle formed by 2 chords that intersect inside the circle is 1/2 the sum of the chords' intercepted arcs.
So x = (1/2)( measure of arc AB + the measure of arc CD ) =
(1/2) ( 27 + 49) =
(1/2) ( 76) =
Let me prove this to you, NSS.....
Then angle BDA = 1/2 arc BA = 13.5°
And angle CAD = 1/2 arc CD = 24.5°
And angle x is exterior to triangle DOA
And angle ODA = angle BDA
And angle OAD = angle CAD
So by the exterior angle theorem......angle x =