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The measure of the angle formed by 2 chords  that intersect inside the circle is 1/2 the sum of the chords' intercepted arcs.

So  x   =  (1/2)( measure of arc AB + the measure of arc  CD )  =

(1/2) ( 27 + 49)  =

(1/2) ( 76)  =

38°

Let me prove this to you, NSS.....

Draw  DA

Then angle BDA  =  1/2  arc  BA   =  13.5°

And angle CAD  = 1/2 arc CD  =  24.5°

And angle x   is exterior to triangle DOA

And angle ODA = angle BDA 

And angle OAD = angle CAD

So by the exterior angle theorem......angle x  =

m