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Let \[f(x) = \frac{3x - 7}{x + 1}.\] Find the inverse $f^{-1}(x)$.
Guest Jul 24, 2017
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Like so:

 

\(y = \frac{3x-7}{x+1} \text{ Solve for x }\\ y(x+1)=3x-7\\x(y-3)=-(y+7)\\x = -\frac{y+7}{y-3} \text{ swap y and x and replace y by f^{-1}(x) }\\f^{-1}(x)=-\frac{x+7}{x-3}\)

Alan  Jul 24, 2017

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