How do you calulate this on a calucator (1+.06) 45
How do you calulate this on a calucator (1+.06)^45
In the 2.0calculator give
(1+0.06)\([y^x]\) 45 =
result
\((1+0.06)^{45}=13.7646108274409967946\\ 57138048363008541855273127772980523 \)
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I thought the correct answer should be \((1+0.6)^{45}\approx1532500000\)? (No Offence)
(Oops I accidentally missed a decimal place XD Nevermind the comment above)
The question says 1.06 NOT 1.60 (and it has not been edited) so asinus is correct :)
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