help
Using the distance formula :
AB = sqrt [ (5 - -1)^2 + ( 4 - - 1)^2 ] =
sqrt [ 6^2 + 5^2] =
sqrt [36 + 25] =
sqrt [61] ≈ 7.8 units
What is the length of side AB in the following triangle rounded to the nearest tenth?
\(\begin{array}{|rcll|} \hline AB &=& \sqrt{5^2+6^2} \\ &=& \sqrt{25+36} \\ &=& \sqrt{61} \\ &=& 7.81024967591 \\ &\approx& 7.81 \\ \hline \end{array}\)