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A person measures the angle of depression from the top of a wall to a point on the ground. The point is located on level ground 62 feet from the base of the wall and the angle of depression is 52°. How high is the wall, to the nearest tenth of a foot?

TheBestAquamarine  May 1, 2017
edited by TheBestAquamarine  May 1, 2017
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2+0 Answers

 #1
avatar+79843 
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We can use the tangent here

 

tan (52)  =  H  / 62     where H is the wall height......rearrange as

 

H  = 62 * tan(52)  ≈  79.4 ft.

 

Here's a pic  ......angle DCB  is the depression angle

 

 

 

cool cool cool

CPhill  May 1, 2017
edited by CPhill  May 2, 2017
 #2
avatar+30 
+1

thank you, i was having troublesfrown

TheBestAquamarine  May 1, 2017

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