+42 x= -8/3 , 2(3x^2+24x+48)+1(x-6)=2(1)
IS THE ANSWER EQUAL??????!!
TO EACH OTHER?
+9466 If \(x=\,-\,\frac83\) , does \(2(3x^2+24x+48)+1(x-6)=2(1)\) ?
Replace every " x " with \( -\,\frac83 \) in the second equation.
\(2(3(-\frac83)^2+24(-\frac83)+48)+1((-\frac83)-6)\stackrel{?}{=}2(1) \\~\\ 2(3(\frac{64}{9})-64+48)+(-\frac{26}3)\stackrel{?}{=}2 \\~\\ 2(\frac{64}{3}-16)-\frac{26}3\stackrel{?}{=}2 \\~\\ 2(\frac{16}{3})-\frac{26}3\stackrel{?}{=}2 \\~\\ \frac{32}{3}-\frac{26}3\stackrel{?}{=}2 \\~\\ \frac63\stackrel{?}{=}2 \\~\\ 2=2\quad\text{ true!}\)
