How can you find out x and y through these equations? -2y=6x+12 4y-2x= -2

Let's try this again

-2y=6x+12   → y = -3x- 6    (1)

4y-2x= -2   (2)       putting (1) into (2) we have

4(-3x-6)-2x = -2   simplify

-12x -24 - 2x = -2      add 24 to both sides

-14x = 22    divide both sides by -14

x = -22/14 = -11/7

And using (1)  ...  y =  -3(-11/7) - 6 =   33/7 - 6  =  33/7 - 42/7 = -9/7

So our solution is (-11/7, - 9/7)

1)   -2y=6x+12 => 2y=12-6x => y=(12-6x)/2     (1)

2)    4y-2x=-2 => 2x=2-4y => x=(2-4y)/2     (2)

Now I take equation (2) and where it has y inside it I put the equation (1) that i have found.

$${\mathtt{x}} = {\frac{\left\{{\mathtt{2}}{\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}\left({\frac{\left({\mathtt{12}}{\mathtt{\,-\,}}{\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{{\mathtt{2}}}}\right)\right\}}{{\mathtt{2}}}}$$   =>   $${\mathtt{x}} = {\mathtt{1}}{\mathtt{\,-\,}}{\frac{\left\{{\frac{\left({\mathtt{48}}{\mathtt{\,\small\textbf+\,}}{\mathtt{24}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{{\mathtt{2}}}}\right\}}{{\mathtt{2}}}}$$    =>  $${\mathtt{x}} = {\mathtt{1}}{\mathtt{\,-\,}}{\frac{\left({\mathtt{24}}{\mathtt{\,\small\textbf+\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{{\mathtt{2}}}}$$  =>  

=> x=1-12+6x => x= -11+6x => 6x-x=11 => 5x=11 => x=11/5 => x=2.2   (3)

Now same thing with the equation (1) but in where i have x i put the (3).

so  (1)=> y=(12-6*2.2)/2 => y=(12-13.2)/2 => y=-1.2/2 => y=-0.6