How do I find f-1(x) for f (x) = -2x+5÷8
The answer I got was; f-1 (x)= 8/-2 x + 5/-2
But I'm unsure about my answer and my work, can Anyone help me out with this please! & Thank you
+128408 f (x) = -2x+5÷8
Write f(x) as y
y = -2x + (5/8) subtract (5/8) from both sides
y - (5/8) = -2x multiply both sides by -1/2
-(1/2)y + 5/16 = x get a common denominator on the left
[-8y + 5] / 16 = x "exchange" x and y
[-8x + 5] / 16 = y for "y" write f-1(x)
f-1(x) = [-8x + 5]/ 16
Check...putting 0 into the original function leads to 5/8....and putting 5/8 into the inverse leads to 0
+128408 f (x) = -2x+5÷8
Write f(x) as y
y = -2x + (5/8) subtract (5/8) from both sides
y - (5/8) = -2x multiply both sides by -1/2
-(1/2)y + 5/16 = x get a common denominator on the left
[-8y + 5] / 16 = x "exchange" x and y
[-8x + 5] / 16 = y for "y" write f-1(x)
f-1(x) = [-8x + 5]/ 16
Check...putting 0 into the original function leads to 5/8....and putting 5/8 into the inverse leads to 0
