+0  
 
0
143
1
avatar

How do I type in this question?

Guest Mar 31, 2017

Best Answer 

 #1
avatar+90988 
+2

my answer

 

\(y=log_bx\qquad \\ \text{Make x the subject}\\ b^y=b^{log_bx}\\ b^y=x \text{swap x and y over to find the inverse function}\\ b^x=y\\ y=b^x \)

 

So I have determined that  the second funtion is the inverse of the first one.

So this means that they are reflections of one another across the line y=x

so draw the line y=x and reflect each ot the points across it and you will have the points for the second graph.

 

So

(1,0) becomes (0,1)

(2,1) becomes (1,2)

etc    

Melody  Apr 1, 2017
Sort: 

1+0 Answers

 #1
avatar+90988 
+2
Best Answer

my answer

 

\(y=log_bx\qquad \\ \text{Make x the subject}\\ b^y=b^{log_bx}\\ b^y=x \text{swap x and y over to find the inverse function}\\ b^x=y\\ y=b^x \)

 

So I have determined that  the second funtion is the inverse of the first one.

So this means that they are reflections of one another across the line y=x

so draw the line y=x and reflect each ot the points across it and you will have the points for the second graph.

 

So

(1,0) becomes (0,1)

(2,1) becomes (1,2)

etc    

Melody  Apr 1, 2017

5 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details