+33615 Look at the first two terms. Form (x + half the coefficient of the 2nd term)2
This is (x + 6)2 which can be expanded as x2 + 12x + 36
This, in turn can be written as x2 + 12x + 25 + 11, so if x2 + 12x + 25 = 0 then x2 + 12x + 36 = 11
Or (x + 6)2 = 11
x+ 6 = ±√11
x = -6 ±√11
.
+33615 Look at the first two terms. Form (x + half the coefficient of the 2nd term)2
This is (x + 6)2 which can be expanded as x2 + 12x + 36
This, in turn can be written as x2 + 12x + 25 + 11, so if x2 + 12x + 25 = 0 then x2 + 12x + 36 = 11
Or (x + 6)2 = 11
x+ 6 = ±√11
x = -6 ±√11
.
