#1**+1 **

Assuming the gravitational acceleration is \(9.8m/s^2\) in your question.

3 minutes and 22 seconds = 202 seconds

The distance fallen is proportional to one half the square of time times the acceleration:

\(Δx=\frac{1}{2}at^2\)

Plug \(a=9.8m/s^2\) and \(t=202 s\)

\(Δx=\frac{1}{2}9.8\left(202\right)^2\)

\(=4.9(40804)\)

\(=199939.6 m ≈ 200 km\)

(Fun fact: You can fall for over 12 minutes from the solar system's highest cliff- The Verona Rupes on Miranda)

Jeffes02
Aug 8, 2017

#2**0 **

But you can never assume you need to know the vlocity and the rate of witch you are falling

BruinBoy40
Aug 8, 2017