+0  
 
0
42
1
avatar

As stated in title

Guest Oct 25, 2017
Sort: 

1+0 Answers

 #1
avatar+302 
+2

My interpretation: \({d\over dx}({3\over x^2}+5x^2)\)

By sum rule: \({d\over dx}{3\over x^2}+{d\over dx}5x^2\)

By definition of negative exponents: \({d\over dx}3x^{-2}+{d\over dx}5x^2\)

By constant product rule: \(3({d\over dx}x^{-2})+5({d\over dx}x^2)\)

By power rule: \(3(-2x^{-3})+5(2x)\)

Simplify to get \(10x-{6\over x^3}\), which is your final answer. wink

Mathhemathh  Oct 25, 2017

4 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details