y = (-x-6)/(x2+3x)
y = (-x-6)/(x(x+3))
Use partial fraction expansion:
y = A/x + B/(x+3)
y = (A(x+3) + Bx)/(x(x+3)) → ((A+B)x + 3A)/(x(x+3))
For the two sets of y to be the same we must have:
3A = -6 so A = -2
A + B = -1
-2 + B = -1 so B = 1
Hence y = -2/x + 1/(x+3)
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