How to solve the equation g(x)=-5 for x if g(x)=-.5x^2+x+4
Says there's 2 possible solutions
+128460 - 5 = -.5x^2+x+4 multiply through by -2
10 = x^2 - 2x - 8 subtract 10 from both sides
0 = x^2 - 2x - 18 using the quad formula, the solutions are
x = 1 - √19 and x = 1 + √19
+14913 How to solve the equation g(x)=-5 for x if g(x)=-.5x^2+x+4 {nl} Says there's 2 possible solutions
\(-5=-0.5x^2+x+4\)
\(-0.5x^2+x+9=0\)
a b c
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(\large x = {-1 \pm \sqrt{1+4*0.5*9} \over -1}\)
\(\large x=\frac{-1\pm\sqrt{19}}{-1}\)
\(x_1=1-\sqrt{19}=-3.3588989\)
\(x_2=1+\sqrt{19}=5.3588989\)
!
