How is e^x = sin(x) + cos(x) if sin(1)+cos(1) =/ e^1
I don't exactly know what you are trying to derive !!?? But we have:
Cos(Pi) = -1 and Sin(pi) =0, hence:
Cos(pi) + i Sin(Pi) = -1, so that: e^(i*Pi) = -1
There is a mistake...
Correct one : \(e^{ix}=\cos x + i\sin x\)
