Hi Sabi92,
Welcome to the Web2 forum
This is a very strange place to put your question.
Just put it on a new post next time. :)
I really like that fact that you have had a go at it yourself and that you have shown us your work :)
$$\\a(2b^2-c)+b(c-2b^2)$$
what you need to notice here is that the brackets contain the same things except the signs are different.
I am going to look at the second bracket. I could just as easily chosen the first bracket :)
$$c-2b^2 = -1(-c+2b^2)=-1(2b^2-c)$$
so
$$+b(c-2b^2)=+b*-1(2b^2-c) = -b(2b^2-c)$$
so
$$\\a(2b^2-c)+b(c-2b^2)\\\\
=a(2b^2-c)-b(-c+2b^2)\\\\
=a\textcolor[rgb]{0,1,0}{(2b^2-c)}-b\textcolor[rgb]{0,1,0}{(2b^2-c)}\\\\
$Now you have a lots of the green stuff minus b lots of the green stuff$\\\\
$which equals (a-b) lots of the green stuff$\\\\
=(a-b)(2b^2-c)\\\\$$
i dont know how to solve can someone help me
6x=x^2
x=?
$$\small{\text{
$
\begin{array}{rcl}
6x & = & x^2 \\
x^2 - 6x &=& 0 \\
\underbrace{x}_{=0}(\underbrace{x-6}_{=0}) &=& 0 \\
\end{array}
$
}}$$
1. x = 0
2. x-6 = 0 | +6
x = 6
oops im sorry i wrote a wrong question the real question is
6x=2x^2
x=?
so how can i solve it?
i dont know how to solve can someone help me
6x=2x^2
x=?
$$\small{\text{
$
\begin{array}{rcl}
6x & = & 2x^2 \\
2x^2 - 6x &=& 0 \\
\underbrace{x}_{=0}(\underbrace{2x-6}_{=0}) &=& 0 \\
\end{array}
$
}}$$
1. x = 0
2. 2x-6 = 0 | +6
2x = 6 | : 2
x = 6 /2
x = 3
It is similar to what Heureka did.
$$\\6x=2x^2\\
3x^2-6x=0\\
3x(x-2)=0$$
you should be able to finish it :)
i need to do a factorization but i dont get the right answer.help please.
a(2b^2-c)+b(c-2b^2)
that's what i did:
2ab^2-ac+bc-2b^3=a(2b^2-c)+b(c-2b^2)
now what?
Hi Sabi92,
Welcome to the Web2 forum
This is a very strange place to put your question.
Just put it on a new post next time. :)
I really like that fact that you have had a go at it yourself and that you have shown us your work :)
$$\\a(2b^2-c)+b(c-2b^2)$$
what you need to notice here is that the brackets contain the same things except the signs are different.
I am going to look at the second bracket. I could just as easily chosen the first bracket :)
$$c-2b^2 = -1(-c+2b^2)=-1(2b^2-c)$$
so
$$+b(c-2b^2)=+b*-1(2b^2-c) = -b(2b^2-c)$$
so
$$\\a(2b^2-c)+b(c-2b^2)\\\\
=a(2b^2-c)-b(-c+2b^2)\\\\
=a\textcolor[rgb]{0,1,0}{(2b^2-c)}-b\textcolor[rgb]{0,1,0}{(2b^2-c)}\\\\
$Now you have a lots of the green stuff minus b lots of the green stuff$\\\\
$which equals (a-b) lots of the green stuff$\\\\
=(a-b)(2b^2-c)\\\\$$